According to extant evidence, the effect of arresting domestic offenders on thei
ID: 2932509 • Letter: A
Question
According to extant evidence, the effect of arresting domestic offenders on their recidivism is inconsistent. You conducted your own research using a sample of 270 domestic offenders and found the following results:
Recidivism Increased
Recidivism Decreased
Did Not Recidivate
105
95
70
Use the above data to answer questions 2a through 2f
2a) State the null and research hypotheses (2 points)
2b) Indicate the appropriate statistical test (1 point)
2c) With the significance level set at .01, specify your critical value (3 points)
2d) Report the obtained value (5 points)
2e) Declare your decision (i.e., whether to reject or retain the H0; 2 points).
2f) What can you conclude in terms of the observed frequencies in recidivism among the three categories of domestic violence offenders (2 points)?
Recidivism Increased
Recidivism Decreased
Did Not Recidivate
105
95
70
Explanation / Answer
Given table data is as below
------------------------------------------------------------------
Recidivism Increased, 105
Recidivism Decreased, 95
Did Not Recidivate,70
calculation formula for E table matrix
------------------------------------------------------------------
E = 270/3 = 90
calculate chisquare test statistic using given observed frequencies, calculated expected frequencies from above
------------------------------------------------------------------
set up null vs alternative as
null, Ho: no association b/w them OR effect of arresting domestic offenders on their recidivism is inconsistent
alternative, H1: association b/w them OR not Ho.
level of significance, = 0.05
from standard normal table, chi square value at right tailed, ^2 /2 =11.34
since our test is right tailed,reject Ho when ^2 o > 11.34
we use test statistic ^2 o = (Oi-Ei)^2/Ei
from the table , ^2 o = 7.22
critical value
the value of |^2 | at los 0.05 with d.f 3 -1 = 2 is 11.34
we got | ^2| =7.22 & | ^2 | =11.34
make decision
hence value of | ^2 o | > | ^2 | and here we don't reject Ho
ANSWERS
---------------
a.null, Ho: no association b/w them
alternative, H1: association b/w them OR not Ho
b. Chi square test for independence
c. critical value: 11.34
d. test statistic: 7.22
e. decision: reject Ho
Related Questions
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.