Given that the radius of the nucleus of a hydrogen atom is 1.2x 10^-15m and that

Question

Given that the radius of the nucleus of a hydrogen atom is 1.2x 10^-15m and that the radius of the electron cloud of a hydrogenatom is 5.29x10^-11m, how much (i.e., what percentage) of the atomis "empty space"? (Note: you might have to calculate the final twoor three equations by hand of ur calculator does not have enoughsig figs to the right of the deciman point.) I was think thing that I would use r2 forboth givens to figure out total space, but then I don't know how toget a percent from that. Then again I'm not sure if I am looking atit from the right angle. we got a hint remember that the formula for the volume of a shere is4/3r3 and that empty space is equal to the totalspace contained within the electron cloud minus the sapce occupiedby the nucleus. Given that the radius of the nucleus of a hydrogen atom is 1.2x 10^-15m and that the radius of the electron cloud of a hydrogenatom is 5.29x10^-11m, how much (i.e., what percentage) of the atomis "empty space"? (Note: you might have to calculate the final twoor three equations by hand of ur calculator does not have enoughsig figs to the right of the deciman point.) I was think thing that I would use r2 forboth givens to figure out total space, but then I don't know how toget a percent from that. Then again I'm not sure if I am looking atit from the right angle. we got a hint remember that the formula for the volume of a shere is4/3r3 and that empty space is equal to the totalspace contained within the electron cloud minus the sapce occupiedby the nucleus.

Explanation / Answer

Find ratio of volumes V1/V2 = (4/3*pi*r1^3)/{(4/3*pi*r2^2)} = (r1/r2)^3 V1/V2 = (1.2e-15/5.29e-11)^3 = 1.167e-14 Volume of empty space = 1-V1/V2    (decimal)

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