Solve 5b -3a=21 and 7c -3a =42 in terms of \' t \'. The ending answer I have is

Question

                    Solve 5b -3a=21  and 7c -3a =42 in terms of ' t '. The ending answer I                 

                    have is a = 63t + 5t and b =42 + 3t solving for the firrst equation. I need the                 

                                     steps to get to that point. If we plug in a= 63 + 5t and b=42 + 3t into the

original equation: 5b - 3a =21 we get 21 but my question is how do we

solvev the original two equations in terms of " t " to get these two ending

equations: a = 63 + 5t and b =42 + 3t. Can someone please help me.

Explanation / Answer

it's easy take c= 33+ t/7

weget a= 63+5t

substitute in 2nd equation

b=42+ 3t

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