A 41.0 kg box initially at rest is pushed 5.00 m along a rough, horizontal floor

Question

A 41.0 kg box initially at rest is pushed 5.00 m along a rough, horizontal floor with a constant applied horizontal force of 135 N. If the coefficient of friction between box and floor is 0.300, find the following.
(a) the work done by the applied force
J

(b) the increase in internal energy in the box-floor system due to friction
J

(c) the work done by the normal force
J

(d) the work done by the gravitational force
J

(e) the change in kinetic energy of the box
J

(f) the final speed of the box
m/s

Explanation / Answer

(a) the work done by the applied force 135*5= 675 J (b) the increase in internal energy in the box-floor system due to friction 0.300*41*9.81*5 = 602.7 J (c) the work done by the normal force = 0 J as no displacement is taking place in that direction (d) the work done by the gravitational force 0 J, as there is zero displacement in that direction too. (e) the change in kinetic energy of the box 675 - 602.7 J = 72.3 J (f) the final speed of the box 0.5*41*v^2 = 72.3J or v = 1.877 m/s

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