First order system tau = 0.15 s K = 5 mV / degree T(0)= 115 degree C F(t) = T(t)
ID: 2996105 • Letter: F
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First order system tau = 0.15 s K = 5 mV / degree T(0)= 115 degree C F(t) = T(t) =115 + 12sin 2t degree C Output signal is linearly proportional to input signal (that is. K is constant) FIND: Output response. E(t); delta (omega); beta 1 We see immediately from the units of static sensitivity that this first order instrument senses temperature and outputs a voltage signal. Hence, a good system model can be written as tau E+E - KF(t) (3-4). where E(t) represents the output voltage signal Specifically the system model is Written as 0.15 E+E = 5(115 + 12sin2t) mV with E(0) = KT(0) = 575 mV. To solve for E(t), we assume a solution consisting of both homogeneous and particular parts. Final answer: E(t) = 575 + 55.05sin2t - 16.51cos2t + 16.51e -t / 0.15.mV How do i change the output from mV to degree CExplanation / Answer
Given ouput signal is proportional to the input signal......
to get *C from mV, we divide E(t) with K
Hence E(t)in *C =E(t)/k=115+11.01sint2t-3.3cos2t+3.3e^(-t/0.15) Degree C
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