Refrigerant 134a exits a heat exchanger through a .75 in diameter tubing with a
ID: 2997603 • Letter: R
Question
Refrigerant 134a exits a heat exchanger through a .75 in diameter tubing with a mass flow rate of .9 lb/s. The temperature is -15deg F and the quality is .05. Find the velocity of the refrigerant in m/s. Data from the table needed is attached below. PLEASE SHOW ALL WORK!!
Refrigerant 134a exits a heat exchanger through a .75 in diameter tubing with a mass flow rate of .9 lb/s. The temperature is -15deg F and the quality is .05. Find the velocity of the refrigerant in m/s. Data from the table needed is attached below. PLEASE SHOW ALL WORK!!Explanation / Answer
m = Volume flow rate * density
Volume flow rate = Velocty(V) * Area of cross section(A)
density = 1/specific volume at given conditions = 1/v
therefore
m = V*A/v
v at given conditions = vf + x*(vg-vf) = 0.01163 + 0.05*(3.0286-0.01163) = 0.1624785 ft3/lb (look up -15F row from table)
A= (pi*d2)/4 = 0.44179 ft2
from above equation V = mv/A = 0.9*0.1624785/0.44179 = 0.33 ft/s
in m/s = 0.1 m/s
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