Which is the polar form of the parametric equations x = 2 cos theta and y = 2 si

Question

Which is the polar form of the parametric equations x = 2 cos theta and y = 2 sin theta ? r = 2 r = 2 theta r = 4 cos theta sin theta r = 4 cos^2 theta+4sin^2 theta. Which is the polar form of the parametric equations x = 2t and y = t^2? r = 4 tan^2 theta r = 4 sec^2 theta r = 4 sec theta r = 4 tan theta sec theta. A bowling ball is rolled down the alley with a constant velocity of 1.4 m/sec. at an angle of 86 degree to the starting line. The position of the person throwing the bowling ball can be represented by the point (0, 0). Where is the ball after 8 seconds? (0.1, 1.4) (0.6, 8.0) (0.8, 11.2) (11.2, 0.8)

Explanation / Answer

17) x = 2cos (theta) , x^2 =4 cos^2 (theta)

y =2sin (theta) , y^2 =4 sin^2 (theta)

r^2 = x^2 +y^2 = 4 (cos^2 (theta) +sin^2 (theta)) =4

r = 2.

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