Find the vertex of the quadratic function f(x) = x^2 -6x - 16. (3, -25) (-3, -25

Question

Find the vertex of the quadratic function f(x) = x^2 -6x - 16. (3, -25) (-3, -25) (-3, 11) (6, -16) Solve the quadratic equation: 3x^2 - 4x - 4 = 0. (-2, 2/3) (2, - 2/3) (2, -2) Undefined Given f(x) - 5x + 2 and g(x) = x^2 + 5x - 8, find (f middot g) (x). x^2 -10x + 6 x^3 -27x^2 -35x -19 6x^3 + 29x^2 + 30x -15 5x^3 + 27x^2 -30x - 16 Find the inverse of the function: f(x) = 3 squareroot x/6 -3. f^-1 (x) = [6 (x + 3)]^3 f^-1(x) = 6(x^3 + 3) f^-1 (x) = 6(x + 3)^3 f^-1 (x) = 18 (x + 3)Find the maximum or minimum point of the function and state whether it is a maximum or minimum f(x) = -x^2 -14x - 56. (7, 0); minimum (7, 7); maximum (0, 7); minimum (-7, -7); maximum Use the rational zero theorem to find all possible rational zeros for the polynomial function. p(x) = 2x^3 -5x^2 + 7x - 17. plusminus 1, plusminus 17, plusminus 1/2, plusminus 17/2 plusminus 1, plusminus 1/17, plusminus 2, plusminus 2/17 plusminus 1, plusminus 2, plusminus 17

Explanation / Answer

1)
x^2-6x-16 = 0
x^2-6x + 9 - 25 = 0
(x-3)^2 - 25 = 0

clearly vertes is x=3 and y=-25
Answer: a

2)
3x^2-4x-4 = 0
3x^2-6x+2x-4 = 0
3x (x-2)+2(x-2)= 0
(x-2)(3x+2)=0
so,
x=2 and x=-2/3
Answer: b

I am allowed to answer only 1 question at a time

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