Application Calculus Comes Down Problem The Goes up, the Ball and, with a ng a b

Question

Application Calculus Comes Down Problem The Goes up, the Ball and, with a ng a ball up a moves up and a model for the vs then analyze the data by findang a model for the distance vs. time data. 1. Complete the chart below from the data that was collected from the experiment. Time (sec) o 0.4 o 8 2 create a scatterplot of the data on your calculator in L1 in worksheets (Note: Instructions to create a scatterplot are located on D21 in the Miscellaneous section.) want to find a function that will model the data presented. It that the is "parabolic" in its therefore, should be used. So we wi attempt to fit our data with a quadratic function k Recall, from algebra, that the values of h and k represent the vertex (h ,k) of the parabola. B tracing on the of tterplot, you should be able to obtain v k. (Note: You may need to "approximate" the values two data points, not exactly on a data point. h and k because the vertex might be located It appears that h The values of h and k mean something with respect to the activity! Explain what the values of h and k represent with respect to the data collected. k represents 4 can find the alu orafor our equation algebra. Select a close the the chart, say (2.4, point for quadratic equation, along with opYor h and k. The only unknown is a, so solve the equation for a. Round a the values to the nearest your in Record your final function. y -i Enter this equation into YI of your calculator an graph it to see how it fits the data. Ifit doesn't fit well.find your

Explanation / Answer

3) Vertex (h, k) we can clearly take h = 1.60 sec and k = 1.58 , dont need to approximate.

meaning of h and k is ok

( h, k) = (2.4 , 1.86) find value of a: y= a(x -h)^2+k

1.86 = a( 2.4 -1.6)^2 + 1.58

a = 0.437

y = 0.437(x - 1.6)^2 + 1.58 ( final function )

Now you can graph.

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