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Chapter 5 forum Chapter 5 forum Important Note: All Forums must be submitted in

ID: 3040257 • Letter: C

Question

Chapter 5 forum Chapter 5 forum Important Note: All Forums must be submitted in the forum section ONLY. through emails, fax, hand delivery, etc... or any other method except Mak e sure you click on post when you are done. I will not accept forums Need help with this question? view my video on probability. Cancer No Cancer 6130 3492 9622 Total 6432 3568 Positive Mammogram 302 378 Total The table above shows the results of 10000 female patients who had a Mammogram done during a certain period of time. One patient is selected at random, a) what is the probability that the patient had no cancer? b) what is the probability that the patient had a positive Mammogram c) What is the probability that the patient had no cancer given that the Mammogram was negative? and no cer? Respond

Explanation / Answer

From the given table

a) the probability of patient had no cancer is = ratio of total no cancer patients and total females 10000 = 9622 ÷ 10000 = 0.9622

b) the probability that the patient had a positive mammogram and no cancer = intersection of positive mammogram and no cancer divided by total females = 6130 ÷ 10000 = 0.6130

c) the probability of the patient had no cancer given that the mammogram is negative = intersection of no cancer and negative mammogram divided by total negative mammogram = 3492 ÷ 3568 = 0.9787

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