There are a hundred bags each containing a $1. Each turn the person opens a rand
ID: 3042691 • Letter: T
Question
There are a hundred bags each containing a $1. Each turn the person opens a random bag and takes the $1 unless the bag is already empty. The money is not replaced. The person plays the game for 50 turns.How likely is it that a given bag will be opened at least once during the game? (My guess is 1-(99/100)^50)
What is the person's expected win? There are a hundred bags each containing a $1. Each turn the person opens a random bag and takes the $1 unless the bag is already empty. The money is not replaced. The person plays the game for 50 turns.
How likely is it that a given bag will be opened at least once during the game? (My guess is 1-(99/100)^50)
What is the person's expected win?
How likely is it that a given bag will be opened at least once during the game? (My guess is 1-(99/100)^50)
What is the person's expected win?
Explanation / Answer
probability that a bag has been opened at least will not get opened) =1-(99/100)50 =0.395
as person's win X =X1+X2+X3+....+Xn
therefore E(X) =E(X1)+E(X2)+E(X3)+...E(Xn) =0.395+0.395+0.395+... 100 times =$39.5
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