An election is held among six candidates, name A through F. There are 57 voters

Question

An election is held among six candidates, name A through F. There are 57 voters in this election. Using the method of pairwise comparisons A,B, and C win 2 point each, D wins 4, and F wins all of the rest. In this election, who wins the head-to-head comparison? An election is held among six candidates, name A through F. There are 57 voters in this election. Using the method of pairwise comparisons A,B, and C win 2 point each, D wins 4, and F wins all of the rest. In this election, who wins the head-to-head comparison?

Explanation / Answer

There are 6 candidates, so number of pairwise comparisons possible = C[6,2] = 15. So there are 15 points to be won.

A,B,C and D have got 10 points among themselves, and F wins the rest. So F got 5 points and E got 0 points.

From the above points tally, we can conclude that F won all the pair-wise comparisons (because in a pool of 6 candidates, each candidate can have 5 pairs at most). So F is the preferred candidate of all the candidates and F would be the winner in a head-to-head comparison.

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.