Test: Exam 1 Time Remaining: 01:42:56 Submit n This Question: 1 pt 40f 15 (0 com
ID: 3045982 • Letter: T
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Test: Exam 1 Time Remaining: 01:42:56 Submit n This Question: 1 pt 40f 15 (0 complete) This Test: 15 pts p Ha Consider the following data set. 11 14 18 13 12 20 17 11 28 1214 26 15 a) Determine the quartiles for this data. b) Determine the interquartile range for this data. dd , and the third quartile is a) The first quartile is 1, the second quartile is Type integers or decimals.) b) The interquartile range is R(lype an integer or a decimal.) Enter your answer in each of the answer boxes. CO Sample Tests and Quizzes ackExplanation / Answer
Solution:- Given that 11,14,18,13,12,20,17,11,28,12,14,26,15
a) The first quartile is 12 , the second quartile is 14, and the third quartile is 19
b) The interquartile range is 7
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a) Explanation
The first quartile (or lower quartile or 25th percentile) is the median of the bottom half of the numbers. So, to find the first quartile, we need to place the numbers in value order and find the bottom half.
11 11 12 12 13 14 14 15 17 18 20 26 28
So, the bottom half is
11 11 12 12 13 14
The median of these numbers is 12.
The median is the middle number in a sorted list of numbers. So, to find the median, we need to place the numbers in value order and find the middle number.
Ordering the data from least to greatest, we get:
11 11 12 12 13 14 14 15 17 18 20 26 28
So, the median is 14
The third quartile (or upper quartile or 75th percentile) is the median of the upper half of the numbers. So, to find the third quartile, we need to place the numbers in value order and find the upper half.
11 11 12 12 13 14 14 15 17 18 20 26 28
So, the upper half is
15 17 18 20 26 28
The median of these numbers is 19.
b) Explanation
The interquartile range is the difference between the third and first quartiles.
The third quartile is 19.
The first quartile is 12.
The interquartile range = 19 - 12 = 7.
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