The president of Doerman Distributors, Inc., believes that 29% of the firm\'s or
ID: 3046029 • Letter: T
Question
The president of Doerman Distributors, Inc., believes that 29% of the firm's orders come from first-time customers. A simple random sample of 100 orders will be used to estimate the proportion of first-time customers.
a. Assume that the president is correct and p = 0.29. What is the sampling distribution of p for this study? Select from 1 of the 3 answers below:
A normal distribution because np and n(1-p) are both greater than 5A normal distribution because np and n(1-p) are both greater than 5A non normal distribution
A normal distribution because np and n(1-p) are both greater than 5A normal distribution because np and n(1-p) are both less than 5A non normal distribution
A non-normal distribution
b. What is the probability that the sample proportion will be between .18 and .40 (to 4 decimals)?
c. What is the probability that the sample proportion will be between .23 and .35 (to 4 decimals)?
Explanation / Answer
here mean proportion =0.29
and std error =(p(1-p)/n)1/2 =0.0485
1) A normal distribution because np and n(1-p) are both greater than 5
b) P(0.18<P<0.40) =P((0.18-0.29)/0.0485<Z<(0.40-0.29)/0.0485)=P(-2.2696<Z<2.2696)=0.9884-0.0116 =0.9768
c) P(0.23<P<0.35) =P((0.23-0.29)/0.0485<Z<(0.35-0.29)/0.0485)=P(-1.2380<Z<1.2380)=0.8921-0.1079=0.7843
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