What is the right answer for Q18? (A, B are not right) The probability that I ge

Question

What is the right answer for Q18? (A, B are not right)

The probability that I get an Ace or a King is 1 - (44c5/52c5) = 0.58

The sum of probability that I get Ace and King is 2(1-(48c5/52c5)) = 0.68

Part Il: Applications I will be dealt 5 cards from a well shuffled standard deck of 52 playing cards Problem 13 The probability of the event that I get an Ace or a King is (Q17) A: less than sum of the chance that I get an Ace and the chance that I get a King, because (Q18) the A: one event is a subset of the other B: the events are mutually exclusive C: the intersection of the events is not empty D: the events are dependent E: the events are independent F: none of the above ading Save Answers

Explanation / Answer

here it should be C:

as P(A)+P(B) = P(A U B)+P(A n B)

hence P(A UB ) <P(A) +P(B) only when P(A n B) is not equal to 0.

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