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6. A box contains 7 green, 3 yellow, and 2 orange marbles. a. (1) One marble is

ID: 3060662 • Letter: 6

Question

6. A box contains 7 green, 3 yellow, and 2 orange marbles. a. (1) One marble is randomly selected. What's the probability that the marble is green or orange? b. (1) Two marbles are randomly chosen with replacement. Find the probability that one marble vwill e yellow and one marble will be orange. 7.(2) A temp agency has 15 secretaries and 4 bookkeepers available. Company ABC needs 5 secretaries and 2 bookkeepers. How many possible ways can the temp agency provide the 5 secretaries and 2 bookkeepers? 8.(1) A lottery picker has 40 numbered balls in a lottery basket. 5 balls are randomly drawn. How many different ways can 5 balls be drawn if order is not important? 9. A bag contains five slips of paper labeled 2, 4,6.8 and 10 a. (1.5) Two papers are randomly selected, without replacement i. List the elements in the sample space i. How many elements are in the sample space for the experiment? b. (.5) What is the probability that the first slip of paper had a number less than 6 and the second slip of paper had a number more than 3?

Explanation / Answer

6:

Total number of marbles: 7+3+2 = 12

(a)

Out of 12 marbles, 7 are green so

P(green) = 7/12

Out of 12 marbles, 2 are orange so

P(orange) = 2/12

So the probability that selected marble is green or orange is

P(green or orange) = P(green) + P(orange) = 7/12 + 2/12 = 9/12 = 0.75

(b)

Since marbles are drawn so draws are independent. Therefore

P(yellow and orange) = P(yellow)P(orange) = (3/12) * (2/12)= 0.0417

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