Here are the red blood cell counts (in 106 cells per microliter) of a healthy pe
ID: 3062927 • Letter: H
Question
Here are the red blood cell counts (in 106 cells per microliter) of a healthy person measured on each of 15 days 5.4 5.1 4.9 5.3 5.6 5.2 5.5 5.2 5.0 5.3 5.2 4.8 5.4 5.2 5.1 Find a 95% confidence interval estimate of , the true mean red blood cell count (in 106 cells per microliter) for this person during the period of testing. (Round your answers to three decimal places Please provide all 10 cells per microliter to 10° cells per microliter may need to use the apropriate appendix table or technology to answer this questionthe steps and do Need Helpf-Read it- Talk to a Tutor not use excel to find std. dev!!!! #2 -/10 points My Notes Ask Your Teacher You want to rent an unfurnished one-bedroom apartment for next semester. You take a random sample of 10 apartments advertised in the local newspaper and record the rental rates. Assume the rental rates are normally distributed. Here are the rents (in dollars per month) 345, 310, 395, 315, 695, 335, 315, 355, 310, 390 Find a 95% confidence interval for the mean monthly rent for unfurnished one-bedroom apartments available for rent in this communityExplanation / Answer
#1.
Sum of given numbers = 76
mean (xbar) = 76/15 = 5.09
Variance = sum ((xbar - x)^2)/(n-1)) = 0.2407
std. dev. = sqrt(0.2407) = 0.4906
n = 15
mean = 5.09
t-value of 95% CI = 2.1448
std. dev. = 0.4906
SE = std.dev./sqrt(n) = 0.1267
ME = t*SE = 0.2717
Lower Limit = Mean - ME = 4.8217
Upper Limit = Mean + ME = 5.3650
95% CI (4.8217 , 5.365 )
#2.
Sum of given numbers = 3765
mean (xbar) = 3765/10 = 376.5
Variance = sum ((xbar - x)^2)/(n-1)) = 13505.83
std. dev. = sqrt(13505.83) = 116.2146
n = 10
mean = 376.5
t-value of 95% CI = 2.2622
std. dev. = 116.2146
SE = std.dev./sqrt(n) = 36.7503
ME = t*SE = 83.1349
Lower Limit = Mean - ME = 293.3651
Upper Limit = Mean + ME = 459.63492
95% CI (293.3651 , 459.6349 )
x (x-xbar)^2 5.4 0.09404 5.1 0.00004 4.9 0.03738 5.3 0.04271 5.6 0.25671 5.2 0.01138 5.5 0.16538 5.2 0.01138 5 0.00871 3.5 2.53871 5.2 0.01138 4.8 0.08604 5.4 0.09404 5.2 0.01138 5.1 0.00004Related Questions
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.