(2 points) A professional Rock, Paper, Scissors player can win a single game (tr
ID: 3064960 • Letter: #
Question
(2 points) A professional Rock, Paper, Scissors player can win a single game (trial) with probability 0.54. The player is up against an opponent. What is the probability that the player will win 2 games before the opponent wins 2 games? Hint You want to add several values of a negative binomial distribution u(m, k, p) with k being the number of games needed to win and p being the probability of winning What values of m (the number of games played) do you want? Can the player get 2 wins in 1 game? Can the player get 2 wins over 2 games without the opponent getting 2 wins? How about 3 games? 4? What is the probability that the player will win 1 game before the opponent wins 2 games?Explanation / Answer
1)P(player wins 2 games before opponent wins 2 gmaes)=P(player wins both games+player wins then opponent then player wins+oponnent wins and player wins next two games) =0.54*0.54+0.54*0.46*0.54+0.46*0.54*0.54
=0.559872
2)
P(player win 1 game before opponent wins 2) =P(player wins+opponent wins and player wns) =0.54+0.46*0.54
=0.7884
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