please help me I\'m so confused KO B https://www.webassign.net/web/Student/Assig
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please help me I'm so confused
KO B https://www.webassign.net/web/Student/Assignment-Respo bmtdep-19533239 3.R.017 0 In the Western United States there is a saying, "Whisky is for drinken but water is for fighten!" water and water rights have been fought over ever since ranchers and settlers moved into Wyoming, Montana, and the West. Even today farmers and ranchers fight cities and large developments over water from snowmelt that originates deep in the Rocky Mountains. A river starts in a massive and beautiful lake. Then it flows through prime trout fishing areas to a famous waterfall. After it leaves the park, the river is an important source of water for wildife, ranchers, farmers, and cities downstream. How much water does leave the park each year? The annual flow of the river (units 108 cubic r 19 recent years. 25.9 32.4 33.1 19.1 17.5 24.9 21.0 45.1 30.8 34.3 27.1 29.1 25.6 31.2 23.2 24.1 23.9 25.9 18.6 (a) Is there a "guaranteed" amount of water farmers, ranchers, and cities will get from the river each year? O Yes, flows average out to the same value across each year O Yes, flows occur at the same rate at corresponding times throughout the year No, annual flows are a random variable. O No, annual flows change at a steady rate from year to year O Yes, flows occur at a constant rate. (b) What is the "expected" annual flow from the snowmelt? Find the mean, median, and mode. (Round your answers to two decimal places.) mean 27 median 25.9Explanation / Answer
Use R code to solve
Solutionb:
annual_flow <- c(25.9,32.4,33.1,19.1,17.5,24.9,21,45.1,30.8,34.3,27.1,29.1,25.6,31.2,23.2,24.1,
23.9,25.9,18.6)
mean(annual_flow)
MEAN=26.99
to get median
median(annual_flow)
=25.9
MEDIAN=25.9
to gt mode:
25.9 repeats 2 times
MODE=25.9
Solutionc:
range(annual_flow)
sd(annual_flow)
RANGE=MAX-MIN=45.1-17.5= 27.6
STANDARD DEVIATION=6.60
Solutione:
atleast 75% of the values lies in between mean-2sd and mean+2sd
26.98947-2* 6.600665 and 26.98947+2* 6.600665
13.79,40.19
lower limit=13.79
upper limit=40.19
Solutione:
quantile(annual_flow,probs=c(0,0.25,0.50,0.75,1))
0% 25% 50% 75% 100%
17.50 23.55 25.90 31.00 45.10
min=17.50
Q1=23.55
Q2=25.90
Q3=31.00
max=45.10
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