The duratlon of time from first exposure to HIV infection to AIDS diagnosis Is c

Question

The duratlon of time from first exposure to HIV infection to AIDS diagnosis Is called the Incubation perlod. The Incubatlon perlods of a random sample of 7 HINV infected individuals is given below (in years): 2.0 10.5 13.5 12.5 9.5 63 7.2 - Suppose another random sample of 100 persons is taken from the same population, and added to the sample of 7, for a total sample of 107 HIV infected individuals. How will the sample standard deviation of the 107 values compare in value to the sample standard deviation from the original sample of n=7? a. it will be larger b. It will be smaller c. it will be exactly the same value d. While the two values should be "similar", there is no way to predict exactly how the two values will compare

Explanation / Answer

answer:

Arrangement: Given , Random Samples are 12.0, 10.5, 9.5, 6.3, 13.5, 12.5, 7.2 and X be the irregular variable.

a)

Mean=mu=rac{sum_{i=0}^{N}Xi}{N}=rac{12.0+10.5+9.5+6.3+13.5+12.5+7.2}{7}

mu=10.21

Variance=sigma^2=rac{sum{i=0}^{N}(Xi-mu)^2}{N}

=7.39

b)

Standard,,,Deviation=sigma=2.71

c)

Middle discovering Steps:

1. Mastermind the perception is climbing request

6.3, 7.2, 9.5, 10.5, 12.0, 12.5, 13.5

2. On the off chance that tally of perceptions is odd . Here, it is 7 at that point

Median= (rac{n+1}{2})^t^h

Median= (rac{7+1}{2})^t^h

Median= 4^t^h ,,observation=10.5

d) If number over 6.3 were changed to 1.5

perception ends up 1.5, 1.5, 1.5, 6.3, 1.5, 1.5, 1.5

Mean=mu=rac{sum{i=0}^{N}Xi}{N}=rac{1.5+1.5+1.5+6.3+1.5+1.5+1.5}{7}

mu=2.19

Variance=sigma^2=rac{sum{i=0}^{N}(Xi-mu)^2}{N}=3.91

Standard,,,Deviation=sigma=1.81

Middle discovering Steps:

1. Orchestrate the perception is climbing request

1.5, 1.5, 1.5, 1.5, 1.5, 1.5, 6.3

2. In the event that tally of perceptions is odd . Here, it is 7 at that point

Median= (rac{n+1}{2})^t^h

Median= (rac{7+1}{2})^t^h

Median= 4^t^h ,,observation=1.5

Each mean , middle and standard deviation diminishes.

e) New perceptions 12.0, 10.5, 5.2, 9.5, 6.3, 13.1, 13.5, 12.5, 10.7, 7.2, 14.9, 6.5, 8.1, 7 .9

Mean , Median and Standard Deviation will increment in view of the past outcome

Mean=mu=rac{sum{i=0}^{N}Xi}{N}=rac{12.0+10.5+5.2+9.5+6.3+13.1+13.5+12.5+10.7+7.2+14.9+6.5+8.1+7.9}{14}

mu=9.85

Variance=sigma^2=rac{sum{i=0}^{N}(X_i-mu)^2}{N}=9.5

Standard,,,Deviation=sigma=3.07

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