Given : A lake with a surface area of 525arces was monitored over one month.Duri

Question

Given: A lake with a surface area of 525arces was monitored over one month.During that period the inflowwas 30ft3s-1,and a 1.5 inch seepage loss.Thetotal precipitation during the month was 4.25 inches,with anevaporation loss of 6 inches. Find: the change in storage for the lakeduring the month period ( in ft3)         and the change inheight of the lake during the one month period ( in ft) Given: A lake with a surface area of 525arces was monitored over one month.During that period the inflowwas 30ft3s-1,and a 1.5 inch seepage loss.Thetotal precipitation during the month was 4.25 inches,with anevaporation loss of 6 inches. Find: the change in storage for the lakeduring the month period ( in ft3)         and the change inheight of the lake during the one month period ( in ft)

Explanation / Answer

Gain in height is caused by inflow and precipitation: change in height (ft) due to inflow >>(30 ft^3/s)(30*24*60*60s)/(525*43560ft^2) change in height (ft) due to precipitation >>(4.25/12) ft Loss in height is caused by seepage and evaporation: change in height (ft) due to seepage >> - (1.5/12)ft change in height (ft) due to evaporation >> -(6/12) ft so the net change is height is the sum of the above 4changes. to get the change in storage, multiply the above change inheight by total surface area which is 525*43560 ft^2 hope this helps! change in height (ft) due to evaporation >> -(6/12) ft so the net change is height is the sum of the above 4changes. to get the change in storage, multiply the above change inheight by total surface area which is 525*43560 ft^2 hope this helps!

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