An electron in a hydrogen atom falls from a n=4 level to alower level, emitting

Question

An electron in a hydrogen atom falls from a n=4 level to alower level, emitting light with a wavelneth of 486 nm. What valueof n was the lower level to which the electron fell? this is how you do it: 1/(486 x 10^9) =(1.097x10^7)(1/X^2 - 1/4^2)
X = 2 HOW DO YOU DO THE MATH SO THAT X = 2? i do notunderstand how you get 2!!!!!!! An electron in a hydrogen atom falls from a n=4 level to alower level, emitting light with a wavelneth of 486 nm. What valueof n was the lower level to which the electron fell? this is how you do it: 1/(486 x 10^9) =(1.097x10^7)(1/X^2 - 1/4^2)
X = 2 HOW DO YOU DO THE MATH SO THAT X = 2? i do notunderstand how you get 2!!!!!!!

Explanation / Answer

1/(486 x 10^9) = (1.097x10^7)(1/X^2 -1/4^2) divide both sides by (1.097x10^7), (1/(486 x 10^9))/(1.097x10^7) = (1/X^2 -1/4^2) bring the 1/16 over to the left side (1/(486 x 10^9))/(1.097x10^7) + 1/16 = 1/X^2 now you should be able to solve for X. hope this helps!

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