Your little sister has become inordinately fond of guinea pigs and really, reall
ID: 309727 • Letter: Y
Question
Your little sister has become inordinately fond of guinea pigs and really, really, really wants one for her birthday. You visit a breeder that has three possible color combinations for you to choose from: black (BB), brindle (Bb) and cinnamon (bb). If the breeder has 108 black (BB), 84 brindle (Bb), and 8 cinnamon (bb) guinea pigs: What are the observed frequencies of each genotype in the population? What is the observed frequency of the b allele in the population? How many individuals of each genotype would you expect to see in a population of 200 if the population of guinea pigs is in HWE?Explanation / Answer
Part-a:
BB (p2) = 108/200 = 0.54
Bb(2pq) = 84/200 = 0.42
bb (q2) = 8/200 = 0.04
Part-b:
Observed "b allele" frequency
Freq of "B" = p = p2 + 1/2 (2pq) = 0.54 + 1/2 (0.42) = 0.54 + 0.21 = 0.75
Freq of "b" = q = 1-p = 1 - 0.75 = 0.25
Part-c:
EXPECTED GENOTYPE FREQUENCIES (assuming Hardy-Weinberg):
BB (p2) = (0.75)2 = 0.56
Bb(2pq) = 2 (0.75)(0.25) = 0.37
bb (q2) = (0.25)2 = 0.063
EXPECTED NUMBER OF INDIVIDUALS of EACH GENOTYPE:
# BB = 0.56 X 200 = 112
# M13 M17= 0.37 X 200 = 74
# M17 M17 = 0.06 X 200 = 12
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