State Percent State Percent State Percent Alabama 14.6 Maryland 7.3 Pennsylvania
ID: 3126373 • Letter: S
Question
State
Percent
State
Percent
State
Percent
Alabama
14.6
Maryland
7.3
Pennsylvania
9.9
Connecticut
7.6
Massachusetts
10.2
Rhode Island
10.0
Delaware
9.8
Michigan
10.2
South Carolina
11.9
Florida
12.1
Mississippi
15.5
Tennessee
13.3
Georgia
12.6
New Hampshire
7.4
Vermont
10.1
Illinois
10.5
New Jersey
8.1
Virginia
8.1
Indiana
8.2
New York
14.7
West Virginia
15.8
Kentucky
12.5
North Carolina
13.2
Wisconsin
8.8
Maine
9.8
Ohio
11.1
The table above shows that 8.8% (ie, 0.088) of people living in the state of Wisconsin are living below the poverty line. Assume that 25 people are randomly and independently selected from the state of Wisconsin.
Let X = the number of people living below the poverty line within the 25 randomly selected people from Wisconsin.
Find P(X = 1), the probability of ONE person in the randomly selected 25 is living below the poverty line.
State
Percent
State
Percent
State
Percent
Alabama
14.6
Maryland
7.3
Pennsylvania
9.9
Connecticut
7.6
Massachusetts
10.2
Rhode Island
10.0
Delaware
9.8
Michigan
10.2
South Carolina
11.9
Florida
12.1
Mississippi
15.5
Tennessee
13.3
Georgia
12.6
New Hampshire
7.4
Vermont
10.1
Illinois
10.5
New Jersey
8.1
Virginia
8.1
Indiana
8.2
New York
14.7
West Virginia
15.8
Kentucky
12.5
North Carolina
13.2
Wisconsin
8.8
Maine
9.8
Ohio
11.1
Explanation / Answer
Note that the probability of x successes out of n trials is
P(n, x) = nCx p^x (1 - p)^(n - x)
where
n = number of trials = 25
p = the probability of a success = 0.088
x = the number of successes = 1
Thus, the probability is
P ( 1 ) = 0.241156405 [ANSWER]
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