Q: A box of 8 cellphones contains three yellow cellphones and five green cellpho

Question

Q:

A box of 8 cellphones contains three yellow cellphones and five green cellphones. Complete parts (a) through (d) below.

a. If two cellphones are randomly selected from the box without replacement, what is the probability that both cellphones selected will be green?

b. If two cellphones are randomly selected from the box without replacement, what is the probability there will be one green cellphone and one yellow cellphone selected?

c. If three cellphones are selected with replacement (the first cellphone is returned to the box after it is selected), what is the probability that all three will be yellow?

d. If you were sampling with replacement (the first cellphone is returned to the box after it is selected), what would be the answers to (a) and (b)?

P(both green)equals=

P(1 green and 1 yellow)equals=

Explanation / Answer

Probability = favoral cases/total cases

a. If two cellphones are randomly selected from the box without replacement, what is the probability that both cellphones selected will be green?

P(2 greens)=(5/8)(4/7)=5/14

b. If two cellphones are randomly selected from the box without replacement, what is the probability there will be one green cellphone and one yellow cellphone selected?

P(1 green and 1 yellow)=(5/8)(3/7)=15/56

c. If three cellphones are selected with replacement (the first cellphone is returned to the box after it is selected), what is the probability that all three will be yellow?

P(3yellow)=(3/8)(3/8)(3/8)=0.0527

d. If you were sampling with replacement (the first cellphone is returned to the box after it is selected), what would be the answers to (a) and (b)?

P(2 greens)=(5/8)(5/8)=0.39

P(1 green and 1 yellow)=(5/8)(3/8)=0.2343

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