Can anybody help? A manufacturing company makes two types of water skis, a trick
ID: 3141218 • Letter: C
Question
Can anybody help?
A manufacturing company makes two types of water skis, a trick ski and a slalom ski. The relevant manufacturing data are given in the table. (A) If the profit on a trick ski is $30 and the profit on a stator ski is $50, how many of each type of ski should be manufactured each day to realize a maximum profit? What is the maximum profit? The maximum profit is $ The maximum occurs when trick skis and slalom skis are produced (B) Discuss the effect on the production scheduled and the maximum profit if the profit on a slalom skis are produced. The maximum profit $. The maximum occurs when trick skis and slalom skis are produced (C) Discuss the effect on the production schedule and the maximum profit if the profit on a slalom ski increases to $60. The maximum profit $. The maximum occurs when trick skis and slalom skis are produced.Explanation / Answer
Solution:
Let x unit of trick ski and y unit of slao is being produced
Maximize p = 30x + 50y subject to
5x + 4y <= 160
x + y <= 35
using simplex method for
Tableau #1
x y s1 s2 p
5 4 1 0 0 160
1 1 0 1 0 35
-30 -50 0 0 1 0
Tableau #2
x y s1 s2 p
1 0 1 -4 0 20
1 1 0 1 0 35
20 0 0 50 1 1750
therefore optium soulition:
Optimal Solution: p = 1750; x = 0, y = 35
Answer: the maximum profit $ 1750 the maximum occours when 0 trick skis and 35 slalom skis are produced
Now for
if profit decreses on a slalom skie decreases to $ 35
then
Maximize p = 30x + 35y subject to
5x + 4y <= 160
x + y <= 35
using simplex method
Tableau #1
x y s1 s2 p
5 4 1 0 0 160
1 1 0 1 0 35
-30 -35 0 0 1 0
Tableau #2
x y s1 s2 p
1 0 1 -4 0 20
1 1 0 1 0 35
5 0 0 35 1 1225
Optimal Solution: p = 1225; x = 0, y = 35
Answer: the maximum profit $ 1225 the maximum occours when 0 trick skis and 35 slalom skis are produced
Now again
if slalom increases to $ 60
then
Maximize p = 30x + 60y subject to
5x + 4y <= 160
x + y <= 35
using simplex method
Tableau #1
x y s1 s2 p
5 4 1 0 0 160
1 1 0 1 0 35
-30 -60 0 0 1 0
Tableau #2
x y s1 s2 p
1 0 1 -4 0 20
1 1 0 1 0 35
30 0 0 60 1 2100
Optimal Solution: p = 2100; x = 0, y = 35
Answer: the maximum profit $ 2100 the maximum occours when 0 trick skis and 35 slalom skis are produced
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