Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

Finite Test 1 review Name: Molae zayer Circle your answers I. Complete the follo

ID: 3144673 • Letter: F

Question

Finite Test 1 review Name: Molae zayer Circle your answers I. Complete the following table if 2x+y#8 3 4 Also find f(1) 22.What is the slope of the line passing through the points (2,1) and 3, What is the equation if the line from #2 in slope intercept form? 4. What is the slope of the line that passes through the points (-2,4) and 5. What is the line that is parallel to 2x-y=5 and passes through (-1,2) y=2x ty 6: What is the line that is perpendicular to y=1/3r7 and passesthrough (2,5) 7. Find the point of intersection of the lines 2x-y 4 and 4x-3ys-8 8. Find the slope and y-intercept of the line 2x-3y-6 9. For a certain commodity, the supply and demand equations have been estimated by S-4p+ 10 and D -0.5p+19. Find the market price. b. make sure that you can also do a break even problem qg 10 Find the line of best fit -3 -2 0 2

Explanation / Answer

(According to Chegg policy, only four subquestions will be answered. Please post the remaining in another question)

1. 2x + y = 8

x = 0 => y = 8

y = 0 => 2x = 8 => x = 4

x = 2 => 2*2 + y = 8 => 4 + y = 8 => y = 4

y = -1 => 2x - 1 = 8 => 2x = 9 => x = 9/2.

x = -3 => 2*-3 + y = 8 => -6 + y = 8 => y = 14

x = 4 => 2*4 + y = 8 => 8 + y = 8 => y = 0.

The filled table is below:

2. Slope of the line passing through (2,1) and (4,-6)

= ((-6) - 1) / (4 - 2)

= -7 / 2

or -3.5.

3. The equation of a line in slope-intercept form is y = mx + c

Slope m = -7/2

=> y = (-7/2)x + c

Substituting the point (2,1)

=> 1 = (-7/2)*2 + c

=> 1 = -7 + c

=> c = 1 + 7 = 8

The equation of the line is y = (-7/2)x + 8

4. Slope of the line that passes through (-2,4) and (-2,6)

is (6-4) / (-2-(-2)

= 2 / 0

= .

x 0 4 2 9/2 -3 4 y 8 0 4 -1 14 0
Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Drop an Email at drjack9650@gmail.com
Chat Now And Get Quote