Specifications for a part for a DVD player state that the part should weigh betw
ID: 3157985 • Letter: S
Question
Specifications for a part for a DVD player state that the part should weigh between 24.9 and 25.9 ounces. The process that produces the parts has a mean of 25.4 ounces and a standard deviation of .22 ounce. The distribution of output is normal. Use Table-A.
What percentage of parts will not meet the weight specs? (Round your "z" value and final answer to 2 decimal places. Omit the "%" sign in your response.)
Within what values will 99.74 percent of sample means of this process fall, if samples of n = 12 are taken and the process is in control (random)? (Round your answers to 2 decimal places.)
Lower value?
, Upper value ?
a.What percentage of parts will not meet the weight specs? (Round your "z" value and final answer to 2 decimal places. Omit the "%" sign in your response.)
Explanation / Answer
A)
We first get the z score for the two values. As z = (x - u) / s, then as
x1 = lower bound = 24.9
x2 = upper bound = 25.9
u = mean = 25.4
s = standard deviation = 0.22
Thus, the two z scores are
z1 = lower z score = (x1 - u)/s = -2.27
z2 = upper z score = (x2 - u) / s = 2.27
Using table/technology, the left tailed areas between these z scores is
P(z < z1) = 0.0116
P(z < z2) = 0.9884
Thus, the area between them, by subtracting these areas, is
P(z1 < z < z2) = 0.9768
Thus, those outside this interval is the complement = 0.0232 = 2.32% [ANSWER]
**********************************
b)
The standard error in that case is
SE = s/sqrt(n) = 0.22/sqrt(12) = 0.06350853
As the middle area is
Middle Area = P(x1<x<x2) = 0.9974
Then the left tailed area of the left endpoint is
P(x<x1) = (1-P(x1<x<x2))/2 = 0.0013
Thus, the z score corresponding to the left endpoint, by table/technology, is
z1 = -3.01
By symmetry,
z2 = 3.01
As
u = mean = 25.4
s = standard deviation = 0.06350853
Then
x1 = u + z1*s = 25.20883932
x2 = u + z2*s = 25.59116068
Hence, between 25.21 and 25.59. [ANSWER]
Related Questions
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.