Specifications for a part for a DVD player state that the part should weigh betw

Question

Specifications for a part for a DVD player state that the part should weigh between 25.3 and 26.3 ounces. The process that produces the parts has a mean of 25.8 ounces and a standard deviation of .26 ounce. The distribution of output is normal. Use Table-A. a.What percentage of parts will not meet the weight specs? (Round your "z" value and final answer to 2 decimal places. Omit the "%" sign in your response.) Percentage of parts % b·Within what values will 99.74 percent of sample means of this process fall, if samples of n= 9 are taken and the process is in control (random)? (Round your answers to 2 decimal places.) Lower value. Upper value-

Explanation / Answer

a)

% of parts =94.51% ( please try 94.50% if this does not work)

b) as 99.74% values fall 3 std deviation from mean

hence lower limit =mean -3*Std deviaiton/(9)1/2 =25.54

upper limit =mean +3*Std deviaiton/(9)1/2 =26.06

for normal distribution z score =(X-)/ here mean=       = 25.800 std deviation   == 0.2600

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