A 10-gram point charge starts at rest at the origin, and is constrained to move
ID: 3161274 • Letter: A
Question
A 10-gram point charge starts at rest at the origin, and is constrained to move along the x-axis. At x = -2 meters, the electric potential is -100 V; at x = 0 meters, the electric potential is 0 V; at x = +2 meters, the electric potential is + 100 V. At t = 10 seconds, the point charge is observed to be at x = 2 meters and to have a kinetic energy of 800 mu J. Since U = qV, it would appear that the initial electric potential energy of the particle is zero. Why, then, does the particle move? Determine the electric charge of the particle. Determine the particle' momentum at t = 10 seconds. Assuming that the electric potential changes linearly in this region, find the electric field at x = 0 m.Explanation / Answer
(a)potential energy is zero but there is inertia of force due to potential difference so it start moving
(b)at x=2
qV=0.5mv^2
q=0.5mv^2/V=8 uC=8*10^(-6)C
(c)momentum=mv
v=sqrt(2E/m)=0.4
momentum=4*10^(-3) kgm/s
(d)E=V/d=100/2=50 N/C toward -x axis
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.