A new drug is being used to relieve the pain of arthritis. However, the drug may
ID: 3174955 • Letter: A
Question
A new drug is being used to relieve the pain of arthritis. However, the drug may reduce a patient’s heartbeat too much. To investigate the drugs effect on a person’s heartbeat, different dosages of the drug were given to six patients, and 30 minutes later, the decrease in each patient’s heartbeat was recorded.
Dosage X = (2.0, 1.5, 3.0, 2.5, 4.0, 3.0) measured in ml.
Decrease Y = (15, 20, 18, 16, 19, 17) measured in beat per minute.
ANSWER THE FOLLOWING:
1.) using output only... SSE = ? (round 4 decimal places)
2.) using output only... S = ? (round 4 decimal places)
3.) Predict the decrease in heartbeat of a patient that received 2.5 ml of the drug.
4.) Calculate the prediction error for the heartbeat of a patient that received 2.5 ml of the drug.
5.) Test if the x is significant to the prediction of y. start with Ho and Ha then show your test statisitic, decision and finally write a conclusion.
1,5 2.5 2.5 The REG Procedure Model: Linear Regression Model Dependent Variable: Y Number of Observations Read 12 Number of Observations Used Number of Observations with Missing Values 6 Analysis of Variance Sum of Mean DF Squares Square F Value Pr F Source Model 1 0.26087 0.26087 0.06 0.8178 4 17.23913 4.30978 Error Corrected Total 5 17.50000 Root MSE 2.07600 R-Square 0.0149 11.86287 Coeff Var Parameter Estimates Parameter Standard Variable DF Estimate Error t Value Pr Iti Intercept 1 16.80435 2.95182 5.69 0.0047 1 0.26087 1.06033 0.25 0.8178 resi predicted Y 15 17 .326086957 14.261940399 20.390233514 10.798331697 23.853842216 2.326086957 20 17.195652174 13.032296842 21.359007505 10.085369324 24 305935024 2.8043478261 18 17 15.037432477 20.136480567 11.2843644 23.889548643 0.4130434783 16 17.456521739 15.052807418 19.86023606 11.211488742 23.701554736 1.456521739 19 17.847826087 13.271290366 22.424361808 10.487984119 25.207668055 1.152173913 11.2843644 23.889548643 -0.586956522 17 17.586956522 15.037432477 20.136480567 17.456521739 15.052807418 19.85023606 11.211488742 23.701554736Explanation / Answer
FRom the tables we will predict values:
1. SSE = 17.2391
2. S = 4.3098
3. 16.80435+.26087*2.5 = 17.4565
4. Prediction error = -1.4562
5.
Ho: MuX = 0
Ha: MuX != 0
t = Coeff/SE for variable X = .26087/1.06033 = .25, the p value is .81782 which is more than .05 ( the regular value which we take)
Conclusion - X is insigificant because p value > .05
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