The capacity of an elevator is 8 people or 1232 pounds. the capacity will exceed
ID: 3176402 • Letter: T
Question
The capacity of an elevator is 8 people or 1232 pounds. the capacity will exceed if 8 people have weights with a mean greater than 1232/8= 15 pounds. Suppose the people have weights that are normally distributed with a mean of 163 pounds and a standard deviation of 30 pounds.
a) Find the probability that if a person is randomly selected, his weight will be greater than 154 pounds.
b) Find the probability that 8 randomly selected people will have a mean that's greater than 154 pounds.
c) Does the elevator appear to have the correct weight limit?
Explanation / Answer
At the very outset, the second line in the question says '1232/8= 15 pounds' which is taken as a typo and the solution is based on 1232/8 = 154
Solution
Back-up Theory
If a random variable X ~ N(µ, 2), i.e., X has Normal Distribution with mean µ and variance 2, then
Z = (X - µ)/ ~ N(0, 1), i.e., Standard Normal Distribution ………………………..(1)
P(X or t) = P[{(X - µ)/ } or {(t - µ)/ }] = P[Z or {(t - µ)/ }] .………(2)
X bar ~ N(µ, 2/n),…………………………………………………………….…….(3),
where X bar is average of a sample of size n from population of X.
So, P(X bar or t) = P[Z or {(n)(t - µ)/ }] …………………………………(4)
Probability values for the Standard Normal Variable, Z, can be directly read off from
Standard Normal Tables or using Excel Function……………………………………..(5)
Now, to work out solution,
Let X = weight of people. Then, given,
‘Suppose the people have weights that are normally distributed with a mean of 163 pounds and a standard deviation of 30 pounds.’
X ~ N(163, 302)
Part (a)
Probability that a person randomly selected, will have weight greater than 154 pounds = P(X > 154)
= P[Z > {(154 - 163)/30}] = P(Z > - 0.3) = 1 - P(Z - 0.3)
= 1 – 0.3821 = 0.6179 ANSWER
[vide (2) under Back-up Theory]
Part (b)
Probability that 8 randomly selected people will have a mean that's greater than 154 pounds = P(Xbar > 154)
= P[Z > {(8)(154 - 163)/30}] [vide (4) under Back-up Theory]
= P(Z > - 0.8485) = 1 - P(Z - 0.8485)
= 1 – 0.1981 = 0.8019 ANSWER
[vide (2) under Back-up Theory]
Part (c)
Does the elevator appear to have the correct weight limit?
Clearly, weight limit is unrealistic since given height distribution of the population,
80% of the time, people cannot use the elevator. ANSWER
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