Researchers are interested in whether a new drug to treat Obsessive Compulsive D

Question

Researchers are interested in whether a new drug to treat Obsessive Compulsive Disorder is effective among adults One group of n = 7 adults takes the drug for one month. A control group of n = 7 adults continues with their typical treatment At the end of the month, OCD sj Tiptoes are measured on a self-report scale. Using a two-tailed test with alpha = .05, use the raw scores provided in the table below to decide if there is a significant difference between the two groups and if the null hypothesis would be rejected or retained. Calculate using pooled variance.

Explanation / Answer

from above:

here degree of freedom =n1+n2-2 =12

and pooled std deviation =((n1-1)s12+(n2-1)s22)/(n1+n2-2))1/2 =13.6251

hence std error =(X1-X2)/std error =-1.2357

for above at 12 degrees of freedom p value =0.2402

as p value is greater then 0.05 level we can not reject null hypothesis that there is no significant difference b/w them

S. no Drug treatment Control 1 18 50 2 43 54 3 28 26 4 50 63 5 20 21 6 41 39 7 32 42 total 232.000 295.000 mean 33.143 42.143 std deviation(S) 12.061 15.027

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