Two physicians at the University of Washington student health center wondered wh
ID: 3180357 • Letter: T
Question
Two physicians at the University of Washington student health center wondered whether there is an association between class absences and gender. Questionnaires were sent to a random sample of 150 students taking the same large introductory Biology course. The questionnaire asked students to report how many days of class they missed during the quarter. Means and standard deviations for the groups are presented below Male Female 4.3 6.8 Mean 3.2 SD Total 28. What test will you use to compare the attendance rates of females and males? A. Z-test B. One sample t-test C. Correlation D. Independent samples t-test E. None of the above 29. What is the null hypothesis for this problem? rate. A. There is a difference between boys and girls in attendance rate. B. There is no difference between boys and girls in attendance C. Boys attend less days than girls D. Girls attend days than boys. E. None of the aboveExplanation / Answer
Given that,
mean(x)=4.3
standard deviation , s.d1=1.2
number(n1)=75
y(mean)=6.8
standard deviation, s.d2 =3.2
number(n2)=75
null, Ho: u1 = u2
alternate, H1: u1 != u2
level of significance, = 0.05
from standard normal table, two tailed t /2 =1.993
since our test is two-tailed
reject Ho, if to < -1.993 OR if to > 1.993
we use test statistic (t) = (x-y)/sqrt(s.d1^2/n1)+(s.d2^2/n2)
to =4.3-6.8/sqrt((1.44/75)+(10.24/75))
to =-6.335
| to | =6.335
critical value
the value of |t | with min (n1-1, n2-1) i.e 74 d.f is 1.993
we got |to| = 6.33504 & | t | = 1.993
make decision
hence value of | to | > | t | and here we reject Ho
p-value: two tailed ( double the one tail ) - Ha : ( p != -6.335 ) = 0
hence value of p0.05 > 0,here we reject Ho
ANSWERS
---------------
null, Ho: u1 = u2
alternate, H1: u1 != u2
test statistic: -6.335
critical value: -1.993 , 1.993
decision: reject Ho
p-value: 0
Q28.
independent samples
Q29.
there is a difference between girls and boys in attendence rate
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