I\'m not sure how to do these Take Home Exam 6.pdf X Secure h ps://ttu.blackboar

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I'm not sure how to do these

Take Home Exam 6.pdf X Secure h ps://ttu.blackboard.com bbcswebdav/pid-2559467-dt-conten rid-13457533 1 /courses /201757-MATH-2345-D01/Take ake%20Home%20Exam%206.pdf (qe-q) The clowing data RRmple shows the number of women and who stand in a recent sample that they Pinterest Trust Recommendations 6. What the proportion 0.286 By 0.450 CO 0768 0.962 7 What is the pooled estimate of p? 087 C00.95 The table from below oontain the observed tequendes of Yes and No responses for populaton 1,2, nd 3. Yes 100 150 Total 240 205 255 The expected frequency of the Yes neaponsesinpopulation 2 is 764 B) 1128 D095. 2.34 B)0.77 CO 568 D) 182 0. The p-value is in the intervat 0.1 to 0.9 B) 0.005 to 0.0 0.025 to 0.05 D00.01 to 0.025 Useful formulas: population and n 4 433 PM 3/30/2017 Ask me anything

Explanation / Answer

Given table data is as below

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calculation formula for E table matrix

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expected frequecies calculated by applying E - table matrix formulae

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calculate chisquare test statistic using given observed frequencies, calculated expected frequencies from above

^2 o = 0.78

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set up null vs alternative as
null, Ho: no relation b/w X and Y OR X and Y are independent
alternative, H1: exists a relation b/w X and Y OR X and Y are dependent
level of significance, = 0.05
from standard normal table, chi square value at right tailed, ^2 /2 =5.991
since our test is right tailed,reject Ho when ^2 o > 5.991
we use test statistic ^2 o = (Oi-Ei)^2/Ei
from the table , ^2 o = 0.781
critical value
the value of |^2 | at los 0.05 with d.f (r-1)(c-1)= ( 2 -1 ) * ( 3 - 1 ) = 1 * 2 = 2 is 5.991
we got | ^2| =0.781 & | ^2 | =5.991
make decision
hence value of | ^2 o | < | ^2 | and here we do not reject Ho
^2 p_value =0.677
ANSWERS
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null, Ho: no relation b/w X and Y OR X and Y are independent
alternative, H1: exists a relation b/w X and Y OR X and Y are dependent
test statistic: 0.781
critical value: 5.991
p-value:0.677
decision: do not reject Ho                              

Q8.

105.3

Q9.

0.77

Q10.

0.1 to 0.9

col1 col2 col3 row 1 125 100 150 375 row 2 115 105 135 355 TOTALS 240 205 285 N = 730

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