Hi! Can someone please help me answer these questions? Please keep in mind that
ID: 3183486 • Letter: H
Question
Hi! Can someone please help me answer these questions? Please keep in mind that more than one answer is possible for each of the multiple choice questions.
Thank you very much!!!
Explanation / Answer
Part (a)
ANOVA can only say if there is a difference in the effect among the treatment groups. But, it cannot throw any light on whether a particular treatment effect is more than one other treatment effect. The latter can be assessed only by a post hoc test. With particular reference to the given question, ANOVA can only say if different snacks have different effects or different test timing have different effect and also say if different snack-timing combinations have different effects (this is termed as ‘interaction’ effect). But, it cannot say if candy is better than protein snack with respect to test score or 12 noon is a better timing than 10 am with respect to test score. It can of course say if snack-timing combinations have varying effects as a whole, but not individually.
Based on this, answer to the question is: first and the last questions can be answered by ANOVA.
ANSWER
Part (b)
With respect to the timings, the graph shows a downward trend from 10 to 11 to 12. The mean figure comes down from 90.2 to 87.7 to 86.2. Thus, it would be right to guess that the means are different and hence first hypothesis is likely to be accepted, which, in turn implies third will be rejected.
If there is no interaction between snack and timing, in an ideal situation, the graph for a particular snack over the timing would be a straight line. This is more or less true for ‘red’ graph (protein snack), but not so for others. Also, taking two extremes, candy-10 is 92 while no-snack-12 is just 83. These two should lead us to believe the interaction effect is significant, implying second hypothesis will be rejected.
Thus, second and third hypotheses are likely to be rejected. ANSWER
Part (c)
The ANOVA model is
xijk = µ + i + j + ij + ijk, where xijk represent the kth observation in the kth cell of ith row-jth column, µ = common effect, i = effect of ith row, j = effect of jth column, ij = row-column interaction and ijk is the error component which is assumed to be iid Normally Distributed with mean 0 and variance 2.
Assumption on ijk => xijk are independent and normally distributed.
Thus, only statement 1 and 3 are valid. ANSWER
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