Read the scenario below. Answer the questions. Answers must be typed and in your

Question

Read the scenario below. Answer the questions. Answers must be typed and in your own words. Remember to include your name! Answer sheet due at beginning of Diffusion/Osmosis lab You cannot turn in a handwritten copy or email the info to your TA- it must be a typed answer sheet. Scenario A scientist is studying the effect of temperature on fish reproduction. She measures fish reproduction as the number of baby fish produced. The scientist counts the number of baby fish in each tank at noon every day. She uses a Thermosure brand thermometer to verify temperature in each tank. What would be a possible research hypothesis? What would be the null hypothesis? What is the independent variable in this scenario? What is the dependent variable? List two standardized variables. What would be the treatment? What would be a control group for this treatment? Assume the scientist ran a t-test and received a p value of 0.120. What is the probability (in percent) that the difference between the two treatments was due to chance don't overthink this!? Based on the P-value of 0.120, would you reject the null hypothesis?

Explanation / Answer

1) The study of reproduction has to be checked with respect to temperature. The group of fishes are studied under temperature change and other group of fishes who have similar characteristics are studied without temperature treated. Reproduction capabilities of both group are tested.

2) Null hypothsis: There is no significance difference between production of fish and change of temperature

3) Independent variable is temperature

4) Dependent variable is fish production number since the claim is its vaires with temperature.

5) The two standardised variables would be mean and standard deviation

6) Treatment is a gruop of fishes that are treated with temperature study.

7) The control group in this experiment is the group which does not receive any treatment and is used as a benchmark against which other test results are measured.

This group includes individuals who are very similar in many ways to the individuals who are receiving the treatment, in terms of age, size, reproduction capability etc..

8) If p value is greater than 0.05, then there is no significance difference between treatments and groups.

So, p = 0.12 indicates probability that difference between the two treatments was due to the chance is 1

9) Accept Null hypothsis

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