4. Perform an appropriate statistical test to determine if there is a significan
ID: 3205276 • Letter: 4
Question
4. Perform an appropriate statistical test to determine if there is a significant difference in abundance among the four species calculated from the quadrat sampling (5pt). Hint: Use an ANOVA on the raw sampling data.
State Ho and Ha (2pt).
What is your p-value (1pt)?
Do you reject or fail to reject your null hypothesis and why (2pt)?
Group # Quadrat # Species A Species B Species C Species D 1 1 0 0 0 0 1 2 1 0 0 0 1 3 0 0 0 0 1 4 1 1 0 0 1 5 0 0 1 1 1 6 0 0 0 0 1 7 0 0 0 0 1 8 0 0 0 1 1 9 0 0 0 0 1 10 0 0 1 0 1 11 0 0 0 0 1 12 0 0 2 0 1 13 0 0 0 0 1 14 0 0 0 0 1 15 0 0 0 0 1 16 1 0 0 0 1 17 0 0 1 0 1 18 0 0 0 0 1 19 0 1 0 0 1 20 0 0 0 0 1 21 0 0 0 0 2 22 0 0 0 0 2 23 1 0 0 0 2 24 0 0 0 0 2 25 1 0 0 1 2 26 1 0 0 0 2 27 0 0 1 0 2 28 0 0 1 0 2 29 0 0 0 0 2 30 0 0 2 0 2 31 0 2 0 0 2 32 0 0 0 0 2 33 0 1 0 0 2 34 0 1 0 0 2 35 0 0 0 0 2 36 0 0 1 0 2 37 0 0 0 0 2 38 0 1 0 0 2 39 0 0 2 1 2 40 0 2 0 0 2 41 0 1 0 0 3 42 0 0 1 0 3 43 0 0 1 0 3 44 0 0 0 0 3 45 0 0 0 0 3 46 0 0 0 0 3 47 0 0 2 0 3 48 0 0 0 0 3 49 0 0 0 0 3 50 0 1 0 0 3 51 0 0 0 0 3 52 0 0 0 0 3 53 1 0 0 0 3 54 0 1 0 0 3 55 0 0 0 0 3 56 0 0 0 0 3 57 0 0 0 0 3 58 0 0 2 0 3 59 0 1 0 1 3 60 0 0 0 0 3 61 0 0 0 0 4 62 0 0 0 0 4 63 0 0 0 0 4 64 0 0 0 0 4 65 0 0 0 0 4 66 0 0 0 1 4 67 0 0 0 0 4 68 0 0 0 0 4 69 0 0 0 0 4 70 1 0 0 2 4 71 0 0 0 0 4 72 0 0 0 0 4 73 1 0 0 0 4 74 0 2 0 0 4 75 0 0 0 0 4 76 1 0 0 0 4 77 0 0 0 0 4 78 1 0 0 0 4 79 0 0 0 0 4 80 0 0 0 0 4 81 0 1 0 0 5 82 0 0 0 0 5 83 0 1 0 0 5 84 0 0 2 0 5 85 0 0 1 0 5 86 0 0 0 0 5 87 1 1 0 0 5 88 0 0 1 0 5 89 0 0 0 0 5 90 0 0 0 0 5 91 0 0 0 0 5 92 0 0 1 0 5 93 0 0 0 0 5 94 0 0 0 0 5 95 0 0 0 0 5 96 0 0 0 1 5 97 0 0 0 0 5 98 0 0 0 0 5 99 0 0 0 0 5 100 0 0 0 0 5 101 0 0 0 1 6 102 0 0 0 0 6 103 0 0 0 0 6 104 0 1 0 0 6 105 0 0 1 0 6 106 0 0 0 0 6 107 0 0 1 0 6 108 0 0 0 1 6 109 0 0 0 0 6 110 0 0 0 0 6 111 0 0 3 0 6 112 0 0 0 1 6 113 0 0 0 0 6 114 0 0 0 1 6 115 0 0 2 0 6 116 0 0 1 0 6 117 0 0 3 0 6 118 0 0 0 0 6 119 0 0 1 0 6 120 0 0 0 0Explanation / Answer
Solution:
Here, we have to use the two way analysis of variance for checking the given claim.
The null and alternative hypothesis for this two ANOVA test is given as below:
Null hypothesis: H0: There is no any significant difference in abundance among the four species calculated from the quadrat sampling.
Alternative hypothesis: Ha: There is a significant difference in abundance among the four species calculated from the quadrat sampling.
We assume the level of significance or alpha value for this test as 0.05.
Now, we have to find the test statistic value F by using the ANOVA table calculations.
The ANOVA output for this test is given as below:
Two way ANOVA
Dependent Variable: Abundance
Source
Sum of Squares
df
Mean Square
F
Sig.
Corrected Model
9.153a
23
.398
1.998
.004
Intercept
13.080
1
13.080
65.658
.000
Species
2.934
3
.978
4.909
.002
Group
1.093
5
.219
1.097
.361
Species * Group
5.237
15
.349
1.753
.039
Error
90.845
456
.199
Total
113.000
480
Corrected Total
99.998
479
The P-value for this test is given as 0.004 which is less than the given level of significance or alpha value 0.05, so we reject the null hypothesis that There is no any significant difference in abundance among the four species calculated from the quadrat sampling.
This means we conclude that there is a significant difference in abundance among the four species calculated from the quadrat sampling.
Two way ANOVA
Dependent Variable: Abundance
Source
Sum of Squares
df
Mean Square
F
Sig.
Corrected Model
9.153a
23
.398
1.998
.004
Intercept
13.080
1
13.080
65.658
.000
Species
2.934
3
.978
4.909
.002
Group
1.093
5
.219
1.097
.361
Species * Group
5.237
15
.349
1.753
.039
Error
90.845
456
.199
Total
113.000
480
Corrected Total
99.998
479
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