An experiment was conducted to compare the filling capability of packaging equip
ID: 3206586 • Letter: A
Question
An experiment was conducted to compare the filling capability of packaging equipment at two different bottling plants. Ten bottles were randomly selected from Plant 1 and the fill volume measured and ten bottles were randomly selected from Plant 2 and the fill volume measured. It is known that fill volume is normally distributed. The data below is the fill volume, in milliliters:
Plant 1 Plant 2
755 751 756 750
753 753 759 756
752 753 755 756
753 754 756 755
752 751 755 756
Perform an appropriate hypothesis test to determine whether Plant 2 is producing an average fill volume that is larger than that of Plant 1. Use = 0.02.
Explanation / Answer
here
hence degree of freedom : v=((s12/n1+S22/n2)2/((s12/n1)2/(n1-1) +(s22/n2)2/(n2-1) ) =14 (rounding it down)
and std error =(s12/n1+S22/n2)1/2=0.806
hence test stat t =(x1-x2)/std error =-3.3489
for which p value =0.002
as p value is less then 0.02 level, we reject that mean are equal and accept the claim that Plant 2 is producing an average fill volume that is larger than that of Plant 1
S. no plant 1 plant 2 1 755 756 2 753 759 3 752 755 4 753 756 5 752 755 6 751 750 7 753 756 8 753 756 9 754 755 10 751 756 total 7527.000 7554.000 mean 752.700 755.400 std deviation(S) 1.252 2.221Related Questions
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