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A personnel director interviewing 10 senior engineers for six job openings has s

ID: 3207876 • Letter: A

Question

A personnel director interviewing 10 senior engineers for six job openings has scheduled seven interviews for the first day and three for the second day of interviewing. Assume that the candidates are interviewed in a random order.

(a) What is the probability that x of the top six candidates are interviewed on the first day?

h(x; 7, 6, 10)h(N; 7, 10, 6)    h(x; 3, 10, 6)h(N; 3, 6, 10)


(b) How many of the top six candidates can be expected to be interviewed on the first day? (Round your answer to two decimal places.)
candidates

Explanation / Answer

here we have to select x out of top 6 hence sample success =x as we require x from top six canditates, sample size=6 which is size of six top candiate, population success=7 total number of samples taken from population. and population size=10 ; population size

from hypergeometric distribution probability =h(x;n,k,N) where x=sample success,N=population size,n=population success; k=sample size

hence h(x;7,6,10)

b) expected candidates can be expected to be interviewed on the first day=nk/N =7*6/10=4.2

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