The computer technical support manager at a small company is available from 8:00

Question

The computer technical support manager at a small company is available from 8:00 AM to 5:00PM each weekday. Historical data show that the manager receives an average of 2.9 requests (Poisson distributed) for technical support per hour.

A) What is the probability that the manager will recieve fewer than 4 requests for technical support in an hour?

** Please make sure you include the calculations, formulas, and any explaination on how to do this problem. Just showing I answer I can't figure out how to do the problem properly. Here are the questions.

Explanation / Answer

Possion Distribution
PMF of P.D is = f ( k ) = e- x / x!
Where   
= parameter of the distribution.
x = is the number of independent trials
P( X < 4) = P(X=3) + P(X=2) + P(X=1) + P(X=0)
= e^-2.9 * 0 ^ 3 / 3! + e^-2.9 * ^ 2 / 2! + e^-2.9 * ^ 1 / 1! + e^-2.9 * ^ 0 / 0!
= 0.6696

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