The compound has an internal rotation about the bond as shown below. The half –

Question

The compound has an internal rotation about the bond as shown below. The half – life of the first order disappearance of the cis form can be measured by NMR spectroscopy. It is measured to be ~10-6 sec (use 1 x 10-6 sec in your calculations) at 25 oC. What is the rate constant for this process? Assuming for this reaction, calculate the height of the barrier to rotation.

The compound HC- O -N 0 has an internal rotation about the 0 N bond as shown below. The half - life of the first order disappearance of the cis form can be measured by NMR spectroscopy. It is measured to be 106 sec use 1 x 10 sec in your calculations) at 25 C What is the rate constant for this process? Assuming ASt- for this reaction, calculate the height of the barierto rotation. see in y H3C O-N cis CIS trans

Explanation / Answer

The reaction is first order reaction so the rate constant and half life has following relation

K = 0.693 / t1/2

K = 0.693 / 10^-6 = 0.693 X 10^6 sec ^-1

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