No need for minitab. Just show to answer this question with explanation For each
ID: 3220326 • Letter: N
Question
No need for minitab. Just show to answer this question with explanation
For each of the following problems should perform test by providing an appropriate critical value. y the Minitab will provide the corresponding P-value. NOTES: 1. You must include a Minitab printout for every problem. 2. Do not round off your answers. Data in the form of counts may be assumed to be measured without error, so that your answers are exact. conclusions. 3. Any time you perform a test you must state Hor HA, and yourExplanation / Answer
here after applying chi square goodness of fit test:
here test stat X2 =4.151
degree of freedom =n-1=3
criitcal value for 0.05 level =7.8147
p value =.0.2457
s p value is high then 0.05 level we can not reject that male p[roportion are equal through out the season
Observed O spring summer fall winter Total males 163 135 71 43 412 females 86 77 40 38 241 Total 249 212 111 81 653 Expected E=rowtotal*column total/grand total spring summer fall winter Total males 157.103 133.758 70.034 51.106 412 females 91.897 78.242 40.966 29.894 241 Total 249 212 111 81 653 chi square =(O-E)^2/E spring summer fall winter Total males 0.221 0.012 0.013 1.286 1.532 females 0.378 0.020 0.023 2.198 2.619 Total 0.600 0.031 0.036 3.483 4.151Related Questions
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