What advertising medium gives a brand the next credibility in influencing brand

Question

What advertising medium gives a brand the next credibility in influencing brand decision? According to a survey, 44% of point to TV, complete parts(a) through (e). a. To conduct a follow-up study that would provide 95% confidence that the pointes estimate is correct to within plusminus 0.05of the population proportion, how large a sample size is sampled ? A sample size of people is needed (Round up to the nearest places) b. To conduct a follow-up study that would provide 99% confidence that the pointes estimate is correct to within plusminus 0.05of the population proportion, how many people need to be sampled ? A sample size of people is needed (Round up to the nearest places) c. To conduct a follow-up study that would provide 85% confidence that the point estimate is correct to within plusminus 0.02 of the population proportion, how large a sample size is required? A sample sine of people required is (Round up to the nearest places) d. To conduct a follow-up study that would provide 99% confidence that the point estimate is correct to within plusminus 0.02 of the population, how many people need to be sampled? A sample size of people is needed. (Round up to the nearest places) e. Discuss the effects of changing the desired confidence level and the acceptable sampling error on sample size requirements. Select all that apply A. The smaller the sampling error desired, the smaller is the sample size required. B. The higher the level of confidence desired, the smaller is the sample size required. C. The smaller the level of confidence desired, the larger is the sample size required. D. The higher the level of confidence desired, the larger is the sample size required. D. The higher the sampling error desired, the larger is the sample size required. F. The smaller the sampling error desired, the larger is sample size required. G. There are no effects on the sample size requirements.

Explanation / Answer

a) here margin of error E =0.05

and for 95% CI, z=1.96

hence sample size =p(1-p)(z/E)2 =~379

b) for 99% CI, z=2.5758

hence sample size =p(1-p)(z/E)2 =~654

c)for margin of error E =0.02

hence sample size =p(1-p)(z/E)2 =~2367

d)sample size =p(1-p)(z/E)2 =4088

e)option D,F are correct

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