A single die is rolled twice. The set of 36 equally likely outcomes is {(1, 1),

Question

A single die is rolled twice. The set of 36 equally likely outcomes is

{(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6), (2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6), (3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6), (4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6), (5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6), (6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6),}.

Find the probability of the following events.

{Write each answer as a reduced fraction (decimals or spaces entered will be counted incorrect) Example: 2/5}

A= event of getting a sum of 9.

B= event of getting a sum of 7.

C= event of getting a sum of 12.

D= event of a summ less than 12.

P(A)=, P(B)=, P(C)=, P(D)=

Explanation / Answer

from above:P(A) ={(3,6),(4,5),(5,4),(6,3)} =4/36 =1/9

P(B) ={(1,6),(2,5),(3,4),(4,3),(5,2),(6,1)} =6/36=1/6

P(C) ={(6,6)}=1/36

P(D) =1-1/36=35/36

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.