The estimate of the population proportion is to be within plus or minus 0.02, wi

Question

The estimate of the population proportion is to be within plus or minus 0.02, with a 90% level of confidence. The best estimate of the population proportion is 0.18. How large a sample is required? (Use z Distribution Table.) (Round the z-values to 2 decimal places. Round up your answer to the next whole number.)

The estimate of the population proportion is to be within plus or minus 0.02, with a 90% level of confidence. The best estimate of the population proportion is 0.18. How large a sample is required? (Use z Distribution Table.) (Round the z-values to 2 decimal places. Round up your answer to the next whole number.)

Explanation / Answer

Z for 90 confidence level is 1.645

Margin of error= z* Standard deviation/sqrt(n)

0.02 = 1.645* sqrt(0.18*0.82/n)

or, n = 1.645^2 *0.18*0.82 / 0.02^2 = 998.52

hence, 999 samples should atleast be taken

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