8-2 Below are percentages for annual sales growth and net sales attributed to lo
ID: 3245708 • Letter: 8
Question
8-2
Below are percentages for annual sales growth and net sales attributed to loyalty card usage at 74 Noodles & Company restaurants.
(b) Find the correlation coefficient. (Round your answer to 3 decimal places. A negative value should be indicated by a minus sign.)
r = _____________________
(c-1) To test the correlation coefficient for significance at = 0.01, fill in the following. (Use the rounded value of the correlation coefficient from part b in all calculations. For final answers, round tcalc to 3 decimal places and the p-value to 4 decimal places. Negative values should be indicated by a minus sign.)
(c-2) There is no significant correlation.
(d) Does it appear that loyalty card usage is associated with increased sales growth?
rev: 11_01_2016_QC_CS-68213
Annual Sales Growth (%) and Loyalty Card Usage (% of Net Sales)(n = 74 restaurants) Store Growth% Loyalty% Store Growth% Loyalty% 1 -7.5 0.9 38 7.2 2.0 2 -7.4 2.6 39 7.3 2.6 3 -6.4 1.6 40 7.9 1.2 4 -4.0 1.8 41 7.9 1.7 5 -3.5 2.6 42 7.9 1.8 6 -1.8 1.3 43 8.1 1.4 7 -1.6 1.2 44 8.2 2.1 8 -1.4 1.8 45 8.6 1.2 9 -1.1 1.8 46 8.8 1.5 10 -0.3 1.7 47 9.0 0.6 11 0.4 1.8 48 9.2 1.9 12 0.5 0.5 49 9.3 2.7 13 1.0 2.6 50 9.4 2.2 14 1.8 2.7 51 9.4 1.4 15 1.8 2.3 52 10.5 1.9 16 1.9 1.7 53 10.5 1.3 17 2.0 1.2 54 10.5 1.4 18 2.0 1.8 55 10.8 0.6 19 4.0 0.7 56 10.8 2.3 20 4.1 1.8 57 11.0 1.2 21 4.1 1.2 58 11.0 0.7 22 4.7 1.8 59 11.0 2.0 23 4.8 1.6 60 11.3 2.0 24 5.0 1.3 61 13.5 2.2 25 5.4 2.0 62 14.0 2.3 26 5.4 2.5 63 15.0 1.5 27 5.9 2.0 64 15.1 0.6 28 6.2 2.5 65 15.4 2.2 29 6.4 2.5 66 17.2 2.5 30 6.5 1.8 67 17.4 0.7 31 6.6 1.2 68 17.5 1.8 32 6.7 1.4 69 17.9 1.8 33 6.9 2.0 70 18.6 2.5 34 6.9 0.9 71 21.6 1.5 35 7.0 1.7 72 24.6 2.7 36 7.1 1.3 73 25.5 0.9 37 7.1 1.9 74 26.9 2.5
Explanation / Answer
We go to excel and copy the values in two columns, one column for Loyalty and the other for Growth. Then we use the function as =correl(data set). We get the value of correlation as 0.035.
Question b)
Answer: r = 0.035
Question c -1)
t = r * sqrt ((n-2)/(1-r^2))
=0.035 * sqrt ((74-2)/(1-0.035^2))
= 0.297
t cal = 0.297
p-value = tdist(0.297,72,2) [ Excel function ]
p-value = 0.7673
Answer:
t cal = 0.297
p-value = 0.7673
Question c -2)
Here p-value is greater than .01 (level of significance); we retain the null hypothesis and we can conclude that there is no significance correlation.
Answer: True
Question d)
Answer: No
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