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take a lest daniela martinet-Google arome i Secure https://www.mathxl.com/Student/Player Test aspx testld-156288174&centerwin; yes Stat Sp17 TR630 am LBcc Test: Last Exam Ch8-Ch10 Sp17 This Question: 4 pts Unted below actual temperatures andhgh temperatures that wereforecast one day ea ser commutass centera es mate Find the 95% cowdence interval Round to one decimal place as needed) Based on the contsenon intervaloan the dam the dnerendes have ameanofobe reeded? O A. Yes, because the cotidence anerva does not inckade aero O B No, because the confidence does not include amo O c Yes, because the confidenoe mervalindades aero OD No, because the contidenoe inervaindudes aero hitlasely that the forecasts acourate? O A Yes, because appears kelytatte dnerences have a mean equato aero OB. Yes, because it appears unliely that the inerences have a meanequal to zero OC No, because appears urikely the dreneroes have a mean equato amo OD No, because appears likely the dnesenoes have a mean equal aero Click lo select your answerts) O Type here to search

Explanation / Answer

95% confidence interval for difference value of actual and forecasted value

95 % confidence interval = xd +- t0.025,4 s/n

= 4.2 +- 2.776 * 5.357 / 5

= (-2.5, 10.9)

(a) as the confidence interval consisits value of zero so we cannot reject the claim tht difference have a mean of 0 (OPtion D is correct)

(b) Yes, it is likely that forecast are accurate because it appears likely that the difference have a mean equal to zero. (option A is correct)

Actual Forecast d 81 72 9 81 71 10 79 82 -3 82 79 3 79 77 2 sum 21 Average (xd) 4.2 std. dev.(s) 5.357

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