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When 200 convicted embezzlers were randomly selected, the mean (x-bar) length of

ID: 3257052 • Letter: W

Question

When 200 convicted embezzlers were randomly selected, the mean (x-bar) length of prison sentence was found to be 22.1 months and the standard deviation was found to be sigma = 8.6 months Tim Evans is running for political office on a platform of being tougher on convicted criminals. Test her claim that prison terms for convicted embezzlers have a mean different than 24 months. alpha = 0.01. What is the p-value? Use four decimal places When 200 convicted embezzlers were randomly selected, the mean (x-bar) length of prison sentence was found to be 22.1 months and the standard deviation was found to be a = 8.6 months. Tim Evans is running for political office on a platform of being tougher on convicted criminals. Test her claim that prison terms for convicted embezzlers have a mean different than 24 months. alpha = 0.01. State the conclusion Since the p-value is greater than the level of significance, there is insufficient evidence. Fail to reject the null hypothesis Since the p-value is less than the level of significance, there is sufficient evidence. Reject the null hypothesis Since the p-value is greater than the level of significance, there is sufficient evidence. Fail to reject the null hypothesis Since the p-value is less than the level of significance, there is insufficient evidence Fail to reject the null hypothesis) Since the p-value is greater than the level of significance there is insufficient evidence. Reject the null hypothesis

Explanation / Answer

10)

Hypothesis:
H0 : mu = 24
Ha: mu is not equal to 24

Test statistic:

n =200 , x = 22.1 s = 8.6

z = ( x - mean)/(s/sqrt(n))
= ( 22.1 - 24) /( 8.6 / sqrt(200))
= -3.124

we need to find p value using z = -3.124
p value = 0.0017

11)

Since the p value is less than the level of significance , there is sufficient evidence . Reject the null hypothesis

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