Assume the cost of an extended 100.000 warranty for a particular SUV following t

Question

Assume the cost of an extended 100.000 warranty for a particular SUV following the normal distribution with a mean of exist1.710 and a standard a) Determine the interval of warranty costs from various companies that are one standard deviation around the mean. The interval of warranty costs that are one standard deviation around the mean ranges from exist to exist (Type integers or decimal. Use ascending order.) b) Determine the interval of warranty costs from various companies that are two standard deviations around the mean. The interval of warranty costs that are two standard deviation around the mean ranges from exist to exist (Type integers or decimal. Use ascending order.) c) Determine the interval of warranty costs from various companies that are three standard deviations around the mean. The interval of warranty costs that are three standard deviation around the mean ranges from exist to exist (Type integers or decimal. Use ascending order.) d) An extended 10

Explanation / Answer

mean = 1710 ,sd = 75

hence

1) within 1 sd =

(1710 - 75 , 1710 +75)

=(1635,1785)

2)

within 2 sd =

(1710 - 2 *75 , 1710 + 2* 75)

=(1560,1860)

3)

within 1 sd =

(1710 -3* 75 , 1710 +3*75)

=(1485,1935)

4) z = (x -mean)/sd = (2010 - 1710)/75 = 4

hence this 4 sd higher

hence option D) is correct

please rate my solution

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